s38 - P38.4 For destructive interference, si = m n and a =...

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P38.4 For destructive interference, 5.00 cm si n0 139 36.0 cm m aa λλ θ == = = . and 7.98 tan d L = gives () 6.50 mtan 7.98 0.912 m dL ° = 91.2 cm d = . *P38.7 The rectangular patch on the wall is wider than it is tall. The aperture will be taller than it is wide. For horizontal spreading we have width width widt hw i dth 9 5 width 0.110 m2 0.012 2 4.5 m n1 632. 81 0 m 5.18 10 m y L a a θλ = = × × For vertical spreading, similarly height 9 4 0.006 0.000 667 16 3 2 . 9.49 10 m . 000 667 h a λ × = × P38.12 min 1.22 y LD 7 3 1.22 5.00 10 0.030 0 2.61 m 7.00 10 y μ × = × = y = radius of star-image L = length of eye = 500 nm D = pupil diameter = half angle P38.17 By Rayleigh’s criterion, two dots separated center-to-center by 2.00 mm would overlap when d . Thus, 33 9 2.00 10 m4 . 00 10 m 13.1 m 1.22 500 10 m dD L −− ×× = × . P38.27 (a) 46 1 2.732 10 cm 2.732 10 7 3 2 nm 3 660 lines cm d × = × = sin d m = : At 10.09 478.7 nm = At , 13.71 647.6 nm =
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At , 14.77 θ 696.6 nm λ = (b) 1 sin d = and so 2 2s i n d = 21 1 22 si n2 n d λλ θθ λθ == = s i ° ) . Therefore, if then gives 1 10.09 = ( 2 s i n10.09 2 20.51 .
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This note was uploaded on 08/31/2010 for the course PHYSICS 7E taught by Professor Staff during the Fall '08 term at UC Irvine.

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s38 - P38.4 For destructive interference, si = m n and a =...

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