PS5 Solutions - s335.£5.25izéégik...

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Unformatted text preview: s335,.£5.25izéégik, g3?5.32Eggs/$22225EEWEeE/i 5a WMWWMJ/um,flmw«ww K3,» WW2 W W W W W W W W W W x135»? W 2% 2 _ \Eéwxg 4 5??? EEgswéfééazse EEEEEEEE§§§ @& WWQWWWMWWSWWWWWQMW @ngmengng WWW W‘, a «my 63 *w X WMWWMWJW/um": 51w? 1/5? WW, m C , 6?: mvngmgvaNI/w» a, méésg figggmém , fimfiwgfimfifigfi % «MA/WM wag E: g y: E mmm “$2 "input Data" P[8] = 12500 [kPa] T[8] = 550 [C] P[9] = 800 [kPa] "P_cfwh=300 [kPa]" P[10] = P_cfwh P_cond=10 [kPa] P[11] = P_cond W_dot_net=250 [MW]*Convert(MW, kW) Eta_turb= 100/100 "Turbine isentropic efficiency" Eta_turb_hp = Eta_turb "Turbine isentropic efficiency for high pressure stages" Eta_turb_ip = Eta_turb "Turbine isentropic efficiency for intermediate pressure stages" Eta_turb_ip = Eta_turb "Turbine isentropic efficiency for iow pressure stages" Eta_pump = 100/100 "Pump isentropic efficiency" "Condenser exit pump or Pump 1 analysis" Fiuid$=’Steam_iAPWS‘ P[1] = P[11] P[2]=P[10] h[1]=enthaipy(Fiuid$,P=P[1],x=0) {Sat’diiquid} v1=voiume(Fiuid$,P=P[1],x=0) s[1]=entropy(Fiuid$,P=P[1],x=0) T[1]=temperature(Fluid$,P=P[1],x=0) w_pump1_s=v1*(P[2]-P[1])”SSSF isentropic pump work assuming constant specific volume" w_pump1=w_pump1_s/Eta_pump "Definition of pump efficiency” h[1]+w_pump1= hi2] "Steady-fiow conservation of energy" s[2]=entropy(Fiuid$,P=P[2],h=h[2]) T[2]=temperature(Fiuid$,P=P[2],h=h[2]) 'Open Feedwater Heater anaiysis" z*h[10] + y*h{7] + (1-y-z)*h[2] = 1*h[3] "Steady—flow conservation of energy" h[3]=enthaipy(Fiuid$,P==P[3],x=0) T[3]=temperature(Fiuid$,P=P[3],X=O) "Condensate ieaves heater as sat. liquid at P[3]" s[3]=entropy(Fiuid$,P=P[3],x=0) 'Boiier condensate pump or Pump 2 analysis" P[5]=P[8} PM] = P[5] P[3]=P[10] v3=voiume(Fiuid$,P==P[3],x=0) w pump2_s=v3*(P[4]-P[3])"SSSF isentropic pump work assuming constant specific volume" w:pump2=w_pump2_s/Eta_pump "Definition of pump efficiency" h{3]+w_pump2= hi4] "Steady-flow conservation of energy" s[4]=entropy(Fiuid$,P=P[4],h=h{4]) T{4]=temperature(Fiuid$,P=P[4],h=h[4]) "Ciosed Feedwater Heater anaiysis" Pi6i=Pi9i y*h[9] + 1*h{4] = 1*h[51 + y*h[6] "Steady-flow conservation of energy” h[51=enthalpy(Fi uid$ P= P[61 x=0) "h[51=h(T[51, P[5]) where T151=Tsat at P191" T151: temperature(Flui Id$ P: P[51h= h[51) "Condensate leaves heater as set liquid at P161" s[51=—entropy(Fluid$P= P[61h=—h[51) h[61= —enthalpy(Fluid$,=P —6P[ 1x =0) T161=—temperature(Fluicl$ P= —8P[ 1,x=0) "Condensate leaves heater as sat, liquid at P[61" s[61=entropy(Fluid$ P= P[6 1x =0) “Trap analysis“ P171 = P[101 y*h[61 = y*h[71 "Steady~flow conservation of energy for the trap operating as a throttle" T[71=ternperature(Fiuid$,P=P[71,h=h[71) s[71=entropy(Fluid$.P=P[71,h=h[71) "Boiler analysis“ q_in + h[51=h[81"SSSF conservation of energy for the Boiler" h[81=enthalpy(Fluid$, T=T[81, P=P[81) s[81=entropy(Fluid$, T=T[81, P=P[81) “Turbine analysis" ss[91=s[81 hs[91=enthalpy(Fluid$,s=ss[91,P=P[91) Ts[91=temperature(Fluid$,s=ss[91,P=P[91) h1g1=h[81~Eta__turb_hp*(h[81~hs[91)"Definition of turbine efficiency for high pressure stages“ T[91=temperature(Fluid$,P=P[91,h=h[91) s[91=entropy(Fluid$,P=P[91,h=h[91) ss[101=s181 hs[101=enthalpy(Fluid$,s=ss[101,P=P[101) Ts[101=temperature(Fluid$,s=ss[101,P=P[101) h[101=h[91~Eta__turb_ip*(h[91~hs[101)"Definition of turbine efficiency for Intermediate pressure stages" T[101=temperature(Fluid$,P=P[101,h=h[101) s1101=entropy(Fluid$,P=P[101,h=h[101) ss[111=s[81 hs[111=enthalpy(Fluid$,s=ss[111,P=P[111) Ts[111=temperature(Fluid$,s=ss[111,P=P[111) h[111=h[101—_Eta turb __lp* (h [10] hs[111)"Definition of turbine efficiency for low pressure stages" T11 11: —temperature(Fluid$ P=—P[111,h=h[1 11) SH hl8 11= entropy(Fluid$ P=P[111h=h[111) 1= y*h[91 + z*h[101 + (1 y~z)*h[111 + w_ turb “SSSF conservation of energy for turbine" “Condenser analysis" (1~y~z)*h[111=q_out+(1~y~z)*h[11"SSSF First Law for the Condenser" "Cycle Statistics" w_net=w_turb — ((1~y-z)*w_pump1+ w_pump2) Eta_th=w_netfq_in W__dot_net = m_dot * w_net “mm 4 rhurt) 1 Wm m [kw 0.7 0.7 1 0.3915 231.5 0.75 0.75 1 0.4045 224.3 0.8 0.8 1 0.4161 218 0.85 1 0.85 1 0.4267 212.5 0.9 1 0.9 1 0.4353 207.9 0.95 1 0.95 1 0.4452 203.8 1 1 1 0.4535 200.1 0.45 r x . . 1 . x 1 . 1 . 235 0.45: mum =0pump / 230 044— —225 S 0.43» —220 E » 1 0.42 «215 0.40 «210 04/ «205 0.39 1 l L i l 2 [\200 n L 1 0.7 0.75 0.8 0.85 0.9 0.9 1 Tltur'b 12500 kPa s [kJ/kg-K] r}: [kg/s] M M m W M W m M M W M M m M u . WWWMNM , J my Q? AW ,iigégfiz, E2%2%Kiz24?,»i§§§§§§§¢§5§ «4W ,NMMMW N ~ memw .; flay f: x 3;; w, m 2/ a. 2%? m : \ my » 2235,22; is$3;iii;iéiéiai:iizzzgé2%s,g:§E§Ez§E§Es§§E§.§,¢..§,§§;gEEEEEEE gag;gzééiéiésiiéizéég EééigiziiiEEEE§;§§§§§§§§ ii???.ééééfiééaégiii _, .. ii?g§§.§2§i§z§igiizézsé {gagwaéawmcm . fl , g g %% mam $2 \gmwgmgwfigghefifiw . WWW/r, Wm: WmWWJWMXW1WAW W 2: réwméawgw fixfiéwé m M2 Xw kg 62 9.3 g 4?; 9/ a .W A, 3 , , _, yaw» ram}: ,_ L as , $32.? d; /» 2 w 3.72 N, $3 awwm...‘ WNW“ mmflwpmw‘m x % , W , 5Q Yaémmwéééw 1.2% w W EM ézisflé; ME , Q fig Esazzaéxfav M: g V 234 g 3% W ; , (29!;5 p , a 5), M: g nu am,” My ,5: 3 mi N M, w 2 W w 3 A»; is fixiééifiggsfl 53w fimfi Cg fikwmgmwmw “wiawangznw m V g “Q 52 ,finxfifigfifigfififi A % “5”" E 39%5 «as: ”a? 5.6 . 0 , .375; g“. {fix W ,. Z :5: M E if} mfakaxfigx a WWWMWWWMWWM 2/ V 9 «f. , «a; 2,,» Wig... Mi)? WV W ...
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