HW7 - PROBLEM 16.5 1.5 m ~ 1 m Knowing that the coefficient...

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Unformatted text preview: PROBLEM 16.5 1.5 m ~ 1 m Knowing that the coefficient of static friction between the tires and the road is 0.80 for the automobile shown, determine the maximum possible acceleration on a level road, assuming (a) four-wheel drive, (b) rear- wheel drive, (c) front-wheel drive. SOLUTION (a) Four-wheel drive: Thus: 0.80mg = ma a = 0.80g = 0.80(9.81 mIs2) = 7.848 mIs2 a = 7.85 mIs2 .... (b) Rear-wheel drive: Thus: NA = OAW + 0.2ma FA = f.JkNB = 0.80(OAW + 0.2ma) = 0.32mg + 0.16ma-:!:- 'LFx = 'L (Fx )etf : FA = ma 0.32mg + 0.16ma = ma 0.32g = 0.84a a = 0.32 (9.81 mIs2) = 3.7371 mIs2 0.84 or a = 3.74 mIs2 .... ,.., ~ 1 PROBLEM 16.5 CONTINUED (c) Front-wheel drive: ~ ~~ I-- = ~ ''''oi t ~ . ~ L0 G--G}) O~5". ~ r=:s t)/ f }I~ .1~8 f.5'~ "'" +} 'LMA = 'L(MAtff: (2.5 m)NB- (1.5 m)W = -(0.5 m)m1 Thus: N B = 0.6W- 0.2m1 FB = J.ikNB = 0.80(0.6W- 0.2m1) = 0.48mg- 0.16m1 0.48mg- 0.16m1 = m1 0.48g = 1.161 a = 0.48(9.81m/s2) = 4.0593 m/s2 1.16 or a = 4.06m/s2- ~--- PROBLEM 16.7 ~.51b I' h G .-:1 ,. 36 in....
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This note was uploaded on 08/31/2010 for the course ENGRMAE 80 taught by Professor Staff during the Summer '08 term at UC Irvine.

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HW7 - PROBLEM 16.5 1.5 m ~ 1 m Knowing that the coefficient...

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