70ahw5sol - Chapter Eight: AC Steady—State Analysis 637...

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Unformatted text preview: Chapter Eight: AC Steady—State Analysis 637 < Draw the frequemgy-éfimam Cil‘ifififl” and; misum‘ie m: f) for [E36 circuit ShGWH in. Fig. P8.” if m?) 2 W $038772? + 386) A, 5C“) 10% m: Figuré P8. ? F SOLUTION: MANAGE J ,wflm.6 7 FL: 9% L213 vi 3 451463 3.99! (La (_ 377 £4517. 8”) V 706 Irwin, Basic Engineering Circuit Analysis, 8/E fiaéfifi Use Thévenin’s theorem to find VO in the Hem/orig in Fig, P886. " TL - r '1 £1 4 00 A f - ' v.1 Q .71 Q 6 00 V V Z; I 5 = + 41C? A i 3‘1 ' ‘ ]2 (l 2 Q V0 .. . - . 2L {3 o ‘ Figure P6286 SOLUTION: 696 ‘ Irwin, Basic Engineering Circuit Analysis, 8/E @fifi U36 source exchangia to determim: VG in. the. network in Fi P876. Figure £38.76 SOLUTION: is ‘1’ izLfl9°A “‘ch K1 11:5 a? ‘ i GP \JL Chapter Eight: { AC Steady-State Analysis 693 $33 Find, V in the network in Fig. P873 using: 811 . emosition. V f) L; 0., , at» max "23‘? i: kWh Wm“?! W Figure P8.73 SOLUTION: El $41: 1:} El : i. ’ZL‘ML Zj\ @ ZB—€L+%A :- ngl. IS +1] Z—J\ m b‘ 21¢ 5L ‘12 - \IDi—.-.:L'S»zx (4.36%) = , E733 «imasv W—\+%E rZngz, 0V5 ~4- _ '21 + '2x a 2‘ 4“ XL. _Z 2L v07. L aft-w ‘ Va, 3 152% /(zz+&,\\ Vega \IS ~23, /L%Y+aj= o «3% Chapter Eight: AC Steady-State Analysis 681 fifié Find, the: voltage 31¢?is the: inductor in the circuit shown in Fig. £98.61 using nodal analysis. Figure 538.6? SOLUTION: V‘: [D [—39.0 A ~V\+\IL +ZI>< 2:0 wink/a rxsfl '3’). J\ ‘1‘ V\ C 141$} +Vz=o I Q V“)fi 1+“ _ \ VZJM O z) Chapter Eight: AC Steady~State Analysis 683 3&3 Uga mézsgh 2133131313 t0 fimi V5, in thgz circuit ghown in Fig P863. .41 Q jQZ/éig V Figurg £38.63 _ SOLUTION: wlgLEe a 35L31>~T1k10 =5) 31‘ "41322 wade“ 333,13?“ :~ .rzl(z+jz.3d31r‘ cs, W321” (“32312 2:24???" m_m‘.—W—am (M..-er mm" ...
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This note was uploaded on 08/31/2010 for the course EECS 70a taught by Professor Staff during the Winter '08 term at UC Irvine.

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70ahw5sol - Chapter Eight: AC Steady—State Analysis 637...

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