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Unformatted text preview: nections. Problem 3 The average length of the CAS is 43. The wasted capacity is 0.04%. Problem 4 The protocol discussed here is a slotted Aloha. Each channel chooses randomly a wavelength among W available channels. The probability of transmission of k packets is given here by a law of Poisson P k = G k eG k ! The throughput is given by S = GP ( success ) = GeG This value is maximum for G=1 so the throughput is 36%. Problem 5 In a slotted ALOHA, the max utilization of a channel is 1/e, so the max bandwidth of a channel is 2.5/e = 0.92 Gbps. There are 8 channels, so the max network bandwidth is 8 × 0.92 = 7.36 Gbps. The max average bandwidth of a single link is then the network bandwidth divided by the number of links, 7.36/(8 × 7)=131 Mbps. 2...
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This note was uploaded on 09/01/2010 for the course ECE 6543 taught by Professor Boussert during the Spring '09 term at Georgia Tech.
 Spring '09
 Boussert

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