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Unformatted text preview: (1p 1 / ( N1)) N2 , therefore the Pr (collision) = 1(1p 1 / ( N1)) N2 Problem 3 Each packet traverses h hops. In a (2,2) ShueNet, h = 2. At each hop, the packet experiences a queueing delay and a transmission delay.The average transmission delay at each node is simply 1 / . The queueing delay can be found using a standard M/M/1 queueing model. The aggregate 1 arrival rate to an arbitrary node is given by: tot = 7 h . Thus, the queueing delay is given by: D q = tot / (  tot ) . The total delay at each node, including the transmission delay is: D = 1 / tot . Since each packet experiences an average of two hops, the average delay is given by: D avg = 2 D = 2 /14 Problem 4 1. In the dedicated wavelength operation, we need 54 wavelengths and 6 in the shared channel operation. 2. The average number of hops is 2.17 3. The total network capacity is 24.88 2...
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This note was uploaded on 09/01/2010 for the course ECE 6543 taught by Professor Boussert during the Spring '09 term at Georgia Institute of Technology.
 Spring '09
 Boussert

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