This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: (1-p 1 / ( N-1)) N-2 , therefore the Pr (collision) = 1-(1-p 1 / ( N-1)) N-2 Problem 3 Each packet traverses h hops. In a (2,2) ShueNet, h = 2. At each hop, the packet experiences a queueing delay and a transmission de-lay.The average transmission delay at each node is simply 1 / . The queueing delay can be found using a standard M/M/1 queueing model. The aggregate 1 arrival rate to an arbitrary node is given by: tot = 7 h . Thus, the queueing delay is given by: D q = tot / ( - tot ) . The total delay at each node, includ-ing the transmission delay is: D = 1 /- tot . Since each packet experiences an average of two hops, the average delay is given by: D avg = 2 D = 2 /-14 Problem 4 1. In the dedicated wavelength operation, we need 54 wavelengths and 6 in the shared channel operation. 2. The average number of hops is 2.17 3. The total network capacity is 24.88 2...
View Full Document
This note was uploaded on 09/01/2010 for the course ECE 6543 taught by Professor Boussert during the Spring '09 term at Georgia Institute of Technology.
- Spring '09