{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Solutions_Homework6

Solutions_Homework6 - Problem 2 The timing diagram is...

This preview shows page 1. Sign up to view the full content.

GEORGIA TECH LORRAINE GEORGIA INSTITUTE OF TECHNOLOGY School of Electrical and Computer Engineering ECE 6543 Fiber Optic Network Spring Semester 2009 Problem 1 Total bandwidth required = 20 × 12 = 240 Mb/s. This cannot be supported by a single transmitter. We could use two wavelengths (2 lasers) at the CO - one at 1.3 μ m and the other at 1.5 μ m. They would be combined using a 1.3/1.5 coupler, and sent through the AWG. The AWG, because of its periodicity, serves as a router for both the wavelengths. Each ONU would have a 1.3/1.5 coupler to select one of the wavelengths.
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Problem 2 The timing diagram is similar to the one of Fig 5.12 of the document, Dynamic Bandwidth Allocation/IPACT. Problem 3 Nearest ONU = 1 km Farthest ONU = 20 km Power of transmitted signal received from nearest ONU = 0.01 × exp(-0.2/10) = 9.8 μ W Power of transmitted signal received from farthest ONU = 0.01 × exp(-0.2 × 20/10) = 6.7 μ W Therefore, the maximum 0-1 threshold adjusting time for the signal = 500 × 3.1 = 1.5 μ s Therefore, the minimum value of guard time = 1.5 μ s 1...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online