Solutions_Homework6 - Problem 2 The timing diagram is...

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GEORGIA TECH LORRAINE GEORGIA INSTITUTE OF TECHNOLOGY School of Electrical and Computer Engineering ECE 6543 Fiber Optic Network Spring Semester 2009 Problem 1 Total bandwidth required = 20 × 12 = 240 Mb/s. This cannot be supported by a single transmitter. We could use two wavelengths (2 lasers) at the CO - one at 1.3 μ m and the other at 1.5 μ m. They would be combined using a 1.3/1.5 coupler, and sent through the AWG. The AWG, because of its periodicity, serves as a router for both the wavelengths. Each ONU would have a 1.3/1.5 coupler to select one of the wavelengths.
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Unformatted text preview: Problem 2 The timing diagram is similar to the one of Fig 5.12 of the document, Dynamic Bandwidth Allocation/IPACT. Problem 3 Nearest ONU = 1 km Farthest ONU = 20 km Power of transmitted signal received from nearest ONU = 0.01 exp(-0.2/10) = 9.8 W Power of transmitted signal received from farthest ONU = 0.01 exp(-0.2 20/10) = 6.7 W Therefore, the maximum 0-1 threshold adjusting time for the signal = 500 3.1 = 1.5 s Therefore, the minimum value of guard time = 1.5 s 1...
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This note was uploaded on 09/01/2010 for the course ECE 6543 taught by Professor Boussert during the Spring '09 term at Georgia Institute of Technology.

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