PS13_2005 - OPTI 201 R Fall 2005 Problem Set XIII Solutions...

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OPTI 201 R Fall 2005 Problem Set XIII Solutions XIII. 1-5 See Ray Trace Below Parallel Ray Entering, nu = 0 to begin R 10 -10 -30 30 t 3 2 1 ? n 1 1.5 1 1.75 1 - φ 0 -0.05 -0.05 0.025 0.025 0 t/n 2 2 0.5714 ? y 3 3 2.7 2.13 1.997571 nu 0 -0.15 -0.285 -0.23175 -0.18181 y 0 -0.1600 -0.3040 -0.3495 nu -008 -0.0800 -0.0720 -0.0796 -0.08834 Ray Trace 1 As portrayed in problem, nu = 3/25=0.12 to begin R 10 -10 -30 30 t 3 2 1 ? n 1 1.5 1 1.75 1 - φ 0 -0.05 -0.05 0.025 0.025 0 t/n 2 2 0.5714 ? y 0 3 2.9400 2.5860 2.5218 nu 0.12 -0.1600 -0.1770 -0.11235 -0.04931 y 0 -0.1600 -0.3040 -0.3495 nu -0.08 -0.0800 -0.0720 -0.0796 -0.08834 Ray Trace 2
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XIII. 1 1.997571 10.9871 0.18181 BFD cm == XIII. 2 3 16.5007 0.18181 EFL cm XIII. 3 0.3495 3.9563 0.08834 4 exit Z cm Is Left to V XIII. 4 3 Ж 0.072 2.586 ( 0.177) ( 0.304) 0.24 nuy nu y cm =−= × × = XIII. 5 Ж 1 ( 2/ 25) 3 0.24 2.5218 3.9581( 0.04931) 2.72 2 Ж 1 ( 0.0883) (2.72) 0.24 ent exit exit nu y cm D cm nu y cm × × = =−− = × × = Note 1: Ж is invariant everywhere in the system. Ж = Ж 3 = Ж ent = Ж exit Note 2: Many students made the mistake of finding BFD using ray trace two. Make sure you have parallel ray coming in, nu = 0, to calculate BFD. Otherwise, you are getting image distance from V4, then you need lens maker formula to find focal length, then BFD.
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This note was uploaded on 09/01/2010 for the course OPTICS 201 taught by Professor Dereniak during the Spring '05 term at UConn.

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PS13_2005 - OPTI 201 R Fall 2005 Problem Set XIII Solutions...

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