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PS9_2005

# PS9_2005 - OPTI 201 R Fall 2005 IX.1 a FOV in horizontal...

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OPTI 201 R, Fall 2005 Problem Set IX IX.1 a) FOV in horizontal direction: y chief 36.5 2 f 100 u chief atan y chief 100 u chief 0.181 = radians FOV 2 u chief . 180 π . FOV 20.685 = in degrees b) FOV in vertical direction: y chief 24.5 2 f 100 u chief atan y chief 100 u chief 0.122 = radians FOV 2 u chief . 180 π . FOV 13.968 = in degrees c) FOV on the diagonal y chief 24.5 2 2 36.5 2 2 u chief 0.122 = radians f 100 u chief atan y chief 100 FOV 2 u chief . 180 π . FOV 24.793 = in degrees IX.2

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IX.3 a) L = 5’10” / 2 = 35” b) W = 24” / 2 =12” c) L=5’10” / 2 = 35” W = 24” / 2 =12” IX.4
Unfold the mirror to solve the problem 15 , 7.5 2 :( ) 58 46.376 sin 7.5 cos7.5 distance : 5 8 45.979 tan 7.5 : oo o from center to long side edge of mirrors as drawn in figure attached ti n and center to long size edge li n from center to where I sit D θ == =+ = = o o 4 41.979 so, after first bounce, '=7.5+15=22.5 41.979 ' 45.437 46.376 cos22.5 cos22.5 second "=22.5+15=37.5 41.979 t"= cos37.5 cos37.5 n D n i n t so will not walk off after first bounce after bounce D =− = === < = = 57.273 ?46.376 so will walk off after the second bounce in in = From above, we know the beam will come off at the upper mirror.

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PS9_2005 - OPTI 201 R Fall 2005 IX.1 a FOV in horizontal...

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