324_Book

# 324_Book

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Unformatted text preview: value, even though the actual format requires only 10 bytes. Array S T U V W Element Size 2 4 4 12 4 Total Size 28 12 24 96 16 Start Address Element ÜS ÜT ÜU ÜV ÜW ÜS · ¾ ÜT · ÜU · ÜV · ½¾ ÜW · Problem 3.18 Solution: [Pg. 145] This problem is a variant of the one shown for integer array E. It is important to understand the difference between a pointer and the object being pointed to. Since data type short requires two bytes, all of the array indices are scaled by a factor of two. Rather than using movl as before, we now use movw. Expression S+1 S[3] &S[i] S[4*i+1] S+i-5 Type short * short short * short short * Value Assembly leal 2(%edx),%eax movw 6(%edx),%ax leal (%edx,%ecx,2),%eax movw 2(%edx,%ecx,8),%ax leal -10(%edx,%ecx,2),%eax Å Å Ñ ÜS · ÜS · ¾ ÜS · ¾ Ñ ÜS · ÜS · ¾ ·¾ ½¼ Problem 3.19 Solution: [Pg. 147] This problem requires you to work through the scaling operations to determine the address computations, and to apply the formula for row-major indexing. The ﬁrst step is to annotate the as...
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## This note was uploaded on 09/02/2010 for the course ELECTRICAL 360 taught by Professor Schultz during the Spring '10 term at BYU.

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