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Unformatted text preview: s-domain. 5 u 2 + 5 2 du s = tan 1 ( u /5) u = s u = = 2 tan 1 s 5 Now we apply the identity for integration in the time-domain: L f ( ) d t = F ( s ) s This implies that we need only divide our previous Laplace-domain result by s . L sin(5 t ) t dt t = 1 s 2 tan 1 s 5...
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- Spring '12