2300_les04

075 m3 calculate the work output under conditions of

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Unformatted text preview: a final volume of 0.075 m3. Calculate the work output under conditions of (a) constant pressure, (b) constant temperature. Data V1 = 0.040 m3 V2 = 0.075 m3 P1 = 500 kPa Model 1) Closed system. 2) Quasi-equilibrium process. 3) Ideal gas: PV = mRT Lesson 4, Geof Silcox, Chemical Engineering, University of Utah 3 II. Energy and the First Law of Thermodynamics 3. Example (cont.) (a) Analysis (constant pressure) Wout = ∫ PdV = P (V2 − V1 ) V2 V1 Wout = 500 kPa ( 0.075 − 0.040 ) m 3 = 18 kJ (b) Analysis (constant temperature) V2 dV mRT dV = mRT ∫ V1 V1 V1 V V ⎛V ⎞ ⎛V ⎞ = mRT ln ⎜ 2 ⎟ = PV1 ln ⎜ 2 ⎟ 1 ⎝ V1 ...
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This note was uploaded on 09/02/2010 for the course PHYS 2300 taught by Professor Silcox during the Fall '09 term at Utah.

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