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Differential work done by the system is for a piston

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Unformatted text preview: that the boundary move P b. Differential work done by the system is, for a piston of area A, 1 δ Wb,out = F ds = PA ds = P dV 2 c. Replacing F with pA is strictly correct only for a quasi-equilibrium (reversible) process d. The total boundary work done by system is area under curve P = f(V) V1 V2 V Wb,out = ∫ P dV V1 V2 (4-2) Lesson 4, Geof Silcox, Chemical Engineering, University of Utah 2 II. Energy and the First Law of Thermodynamics 3. Evaluation of integral (4-2) Wb,out = ∫ P dV V1 V2 Remember that this equation only applies to a quasi-equilibriu...
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