KINETICS - 2(from 0-100s = 1.8x10-5 M s Note that this is...

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Decomp. rate of NO 2 (from 0-100s) = [NO 2 ] / t = 0.0065-0.01 = 100-0 -3.5x10 -5 M / s Time (s) NO 2 NO O 2 0 0.01 0 0 100 0.0065 0.0035 0.0018 200 0.0048 0.0052 0.0026 Formation rate of NO (from 0-100s) = 3.5x10 -5 M / s They are the same because they have the same coefficients 2NO 2 2NO + O 2 By convention rates are always positive Decomp. Rate of NO 2 (from 0-100s) = 3.5x10 -5 M / s Formation rate of O
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Unformatted text preview: 2 (from 0-100s) = 1.8x10-5 M / s Note that this is ½ that of NO 2 and NO Rate of consumption of NO 2 = Rate of formation of NO = 2(Rate of formation of O 2 ) Because the rate of formation of O 2 is ½ that of NO 2 and NO you need to multiply it by 2 to have them equal one another...
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