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# RelativeResourceManager - 3 3OCl 6OH& 2Fe(OH 3 2PO 4 3...

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Chapter 12 Problems 1-8 Even answers: 2) S(+7 +6) Cr (+3 +6), 2Cr 3+ 7H 2 O Cr 2 O 7 2- + 14H + + 6e - , O 3 SOOSO 3 2- + 2H + + 2e - 2HSO 4 - , 7H 2 O + 2Cr 3+ + 3O 3 SOOSO 3 2- 6HSO 4 - + Cr 2 O 7 2- + 8H + 4) 6Fe 2+ + Cr 2 O 7 2- + 14H + 6Fe 3+ + 2Cr 3+ + 7H 2 O (Fe 2+ RA, Cr 2 O 7 2- OA) I’ll let you do the rest, but here are the correct coefficients: b) 5, 4, 12 5, 4, 11 c) 6, 2, 8 3, 2, 4 d) 3, 10, 4, 10 6, 9, 10 (with these you should be able to tell if you got them correct) 6) Cl 2 O 7 + 4H 2 O 2 + 2OH - 2ClO 2 - + 4O 2 + 5H 2 O (Cl 2 O 7 OA, H 2 O 2 RA) (again, I will only give the coefficients for the rest) b) 2, 4, 3 2, 8, 3 c) 3, 4 6, 6, 4 d) 1, 1 1, 1, 1, 2 8) 2FeHPO
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Unformatted text preview: 3 + 3OCl-+ 6OH-& 2Fe(OH) 3 + 2PO 4 3-+ 3Cl-+ H 2 O Problems 9, 11, 13, 17, 19, 27, 31, 34 Even answer: 34) 10 26 and 10 5 Problems 35, 37, 43, 48, 51, 54, 57, 69, 81, 85, 90 Even answers: 48) yes (1.4x10 2 kJ), as written: ˜ -213 kJ/mol hence entropy must be negative 54) electrode, water, electrode, electrode 90) I hate it when this happens. I should have used a fluoride rinse when I was younger. Al creates the anode of a galvanic cell and both Hg and Sn form the cathode portion....
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