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Unformatted text preview: Thus: 0 < P < 4 kPa (VAPOR) 0.004 MPa < P < 1000 MPa (LIQUID) P > 1000 MPa SOLID (ICE) 4. ICE = 920 kg/m 3 P = gH = 920 kg/m 3 9.80665 m/s2 1000 = 9022 118 Pa P = Po + P = 101.325 + 9022 = 9123 kPa See the phase diagram for water: liquid solid interphase => T LS = 1 C 5. Absorption of energy 6. Release of energy Please Note: The students are using a diagram to solve questions 03 & 04. Their values may not be exactly the same as the solution. Please take this into consideration when evaluating their answers....
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This note was uploaded on 09/05/2010 for the course MEEN 315 taught by Professor Ramussen during the Summer '07 term at Texas A&M.
- Summer '07