HW_13_Solution

HW_13_Solution - Liquid water is heated in a chamber by...

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Liquid water is heated in a chamber by mixing it with saturated water vapor. If both streams enter at the same rate, the temperature and quality (if saturated) of the exit stream is to be determined. Assumptions 1 This is a steady-flow process since there is no change with time. 2 Kinetic and potential energy changes are negligible. 3 There are no work interactions. 4 The device is adiabatic and thus heat transfer is negligible. Properties From steam tables (Tables A-5E through A-6E), h 1 h f @ 60 F = 28.08 Btu/lbm h 2 = h g @ 60 psia = 1177.8 Btu/lbm Analysis We take the mixing chamber as the system, which is a control volume since mass crosses the boundary. The mass and energy balances for this steady-flow system can be expressed in the rate form as Mass balance: m m m m m m m m m m m m 2 1 3 2 1 out in (steady) 0 system out in 2 0 Energy balance: 0) pe ke (since 0 3 3 2 2 1 1 out in energies etc. potential, kinetic, internal, in change of Rate (steady) 0 system mass and work, heat, by nsfer energy tra net of Rate out in W Q h m h m h m E E E E E   Combining the two gives   2 / or 2 2 1 3 3 2 1 h h h h m h m h m Substituting, h 3 = (28.08 + 1177.8)/2 = 602.94 Btu/lbm
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This note was uploaded on 09/05/2010 for the course MEEN 315 taught by Professor Ramussen during the Summer '07 term at Texas A&M.

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HW_13_Solution - Liquid water is heated in a chamber by...

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