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Unformatted text preview: IE 131 Solutions for Problems due Jan 27 (Chs 1 and 2) 1.2 A work group of 10 workers in a certain month produced 7200 units of output working 8 hr/day for 22 days in the month. Determine the labor productivity ratio using (a) units of output per worker-hour and (b) units of output per worker-month. (c) Suppose that in the next month, the same work group produced 6800 units but there were only 20 workdays in the month. For each productivity measure in (a) and (b), determine the productivity index for the next month using the prior month as a base. Solution : (a) Productivity measure = units of output per worker-hour LPR = 7200/10(8)(22) = 4.091 units/hr (b) Productivity measure = units of output per worker-month LPR = 7200/10(1) = 720 units/wrkr-mo (c) For LPR in (a), LPR = 6800/10(8)(20) = 4.25 units/hr LPI = 4.25/4.091 = 1.039 = 103.9% For LPR in (b), LPR = 6800/10(1) = 680 units/wrkr-mo LPI = 680/720 = 0.944 = 94.4% 1.4 There are 20 forging presses in the forge shop of a small company. The shop produces batches of forgings requiring a setup time of 3.0 hours for each production batch. Average standard time for each part in a batch is 45 seconds, and there is an average of 600 parts in a batch. The plant workforce consists of two workers per press, two foremen, plus three clerical support staff. (a) Determine how many forged parts can be produced in 1 month, if there are 8 hours worked per day and an average of 21 days per month at one shift per day. (b) What is the labor productivity ratio of the forge shop, expressed as parts per worker-hour? Solution : (a) Time to produce a batch = T B T B = 3.0(60) + (45/60)(600) = 180 + 450 = 630 min = 10.5 hr Hours/month = 8(21) = 168 hr/mo R p = 168/10.5 = 16 batches/mo per press With 20 presses, R p = 20(16) = 320 batches/mo With Q = 600 pc/batch, R p = 320(600) = 192,000 pc/mo (b) Total labor hours during month = 8(21)(2 x 20 + 2 + 3) = 168(45) = 7560 hr/mo...
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- Spring '08
- bar code, Allowance Factor, PFD allowance factor