solution_pdf - ebadi (pe2985) – Chapter 1 – Sherman –...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ebadi (pe2985) – Chapter 1 – Sherman – (74201) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points The mean radius of a planet is 6 . 36 × 10 6 m, and that of its moon is 1 . 47 × 10 8 cm. From this data calculate the ratio of the planet’s surface area to that of its moon. Correct answer: 18 . 7189. Explanation: Let : r planet = 6 . 36 × 10 6 m and r moon = 1 . 47 × 10 8 cm = 1 . 47 × 10 6 m . The surface area of a sphere is 4 π R 2 ∝ R 2 , so the ratio is A planet A moon = R 2 planet R 2 moon = (6 . 36 × 10 6 m) 2 (1 . 47 × 10 6 m) 2 = 18 . 7189 . 002 (part 2 of 2) 10.0 points Calculate the ratio of the planet’s volume to that of its moon. Correct answer: 80 . 9878. Explanation: The volume of a sphere is 4 3 π R 3 ∝ R 3 so the volume ratio is V planet V moon = R 3 planet R 3 moon = (6 . 36 × 10 6 m) 2 (1 . 47 × 10 6 m) 2 = 80 . 9878 . 003 10.0 points Given 1 inch ≡ 2 . 54 cm and 1 foot ≡ 12 inches, how many square centimeters are in 1 . 54 ft 2 ?...
View Full Document

This note was uploaded on 09/06/2010 for the course PHYS 2425 taught by Professor Sherman during the Spring '08 term at Collin College.

Page1 / 4

solution_pdf - ebadi (pe2985) – Chapter 1 – Sherman –...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online