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Unformatted text preview: ebadi (pe2985) – Chapter 1 – Sherman – (74201) 1 This printout should have 10 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points The mean radius of a planet is 6 . 36 × 10 6 m, and that of its moon is 1 . 47 × 10 8 cm. From this data calculate the ratio of the planet’s surface area to that of its moon. Correct answer: 18 . 7189. Explanation: Let : r planet = 6 . 36 × 10 6 m and r moon = 1 . 47 × 10 8 cm = 1 . 47 × 10 6 m . The surface area of a sphere is 4 π R 2 ∝ R 2 , so the ratio is A planet A moon = R 2 planet R 2 moon = (6 . 36 × 10 6 m) 2 (1 . 47 × 10 6 m) 2 = 18 . 7189 . 002 (part 2 of 2) 10.0 points Calculate the ratio of the planet’s volume to that of its moon. Correct answer: 80 . 9878. Explanation: The volume of a sphere is 4 3 π R 3 ∝ R 3 so the volume ratio is V planet V moon = R 3 planet R 3 moon = (6 . 36 × 10 6 m) 2 (1 . 47 × 10 6 m) 2 = 80 . 9878 . 003 10.0 points Given 1 inch ≡ 2 . 54 cm and 1 foot ≡ 12 inches, how many square centimeters are in 1 . 54 ft 2 ?...
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This note was uploaded on 09/06/2010 for the course PHYS 2425 taught by Professor Sherman during the Spring '08 term at Collin College.
 Spring '08
 Sherman
 Physics

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