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ECE2010_EX3

# ECE2010_EX3 - ECE2011 EXAM 3 A09 Name g0 If“ ECE Box...

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Unformatted text preview: ECE2011 EXAM 3 A09 Name : g0 If“; ECE Box Number: , / Problem 1: Finding the Thevenin and Norton equivalent of simple circuits Solve the following problems by ﬁnding the Thevenin and Norton equivalent of of each network at the terminals. You should do this by ﬁrst ﬁnding the short circuit current isc and the open circuit voltage vac. In this problem you will show the most important steps of this process by writing out the equa- tions that you will solve, then the answers. Please write the equations in a completely unsimpliﬁed form, i.e., exactly as would read the equations off the circuit applying the basic principles of nodal analysis and not combining any of the values in each equation. Place your numerical answers on the lines provided to clearly identify the six values: isc, vac, W, 12TH, RN and RTH. Following the two above rules will greatly reduce the effort and increase the accuracy of grading. Thankyou. of 75 3:0 I xU'AJ‘ ’01. é —50 iggl/ , 1 ‘4’»: ,0 _, c L)“, ,«V E32,» ((7 5" (”vii 7“ a J ___’__________________,___. Vl; {0V 25 V1,] ‘5 N—i—M VT”: 7 RT?" on ’v (A M): (m Problem 2 *7 Finding the Thevenin equivalent resistance Solve the lollowing problems by ﬁnding the Thevenin equivalent resistance of of each network at the terminals by using the source killing approach. Draw your source killed circuit in the space provided and then compute the value of Rm. (ISL hr 1 2%“ -SL mu to 51 T (I 20 51/ _ M ______'_______,_.__.2 jaw“; OS so A 62TH” .’ 5031 Cd Problem 3 a Analyzing circuits with dependent sources Solve for the indicated voltages and currents in each of these circuits which have dependent sources. Use Nodal analysis with the indicated ground as the reference. The ﬁrst step in dependent source analysis involves expressing the contolled source’s value (of voltage or current) in terms of the named nodal voltages and other circuit component values - Show in the space provided (ﬁrst in the list) what that equation is in each case. The only variables that appear in the nodal equations should be the nodal voltages named in the circuit diagram — no other variables. Then show the nodal equations that can be used to solve the circuit and the numerical answer. w 5Q (c3 :qu 5 («X 7 c (1)” ’ W ” dig,” \ ;, (~\ 9 / 3 Problem 4 , Voltage Division ﬂﬁ' 3‘). iuw'gwmw.\‘ : [S—O : 35:: :39 i :0 +~5"+2o~% is i 55‘ ‘i 3' Problem 5 A» Current Division Solve for the indicated currents in each case by applying, current division. L3 .9 \LCL \i/L‘ (4 3" 30H 1 [03, 5—31 L? ' L _, ((2: . .3:- : 10A ("3 2 6' {ﬁg 2,") %3 26A ( L, C (1;: V f’ C} W , 1 r. 4., r ...
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