Homework 3 Solutions

# Homework 3 Solutions - lim (kl9356) – Homework 3 –...

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Unformatted text preview: lim (kl9356) – Homework 3 – Weathers – (17104) 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points Two sides of a triangle are 12 . 7 cm and 20 . 4 cm, with the included angle 114 ◦ . a) What is the length of the third side? Correct answer: 28 . 075 cm. Explanation: Basic Concepts: The Law of Cosines states c 2 = a 2 + b 2- 2 ab cos C The Law of Sines states sin A a = sin C c Solution a c b A C We are looking for the side opposite the given angle so c = radicalbig a 2 + b 2- 2 ab cos C 002 (part 2 of 2) 10.0 points b) What is angle opposite the side 12 . 7 cm? Correct answer: 24 . 4092 ◦ . Explanation: sin A a = sin C c A = arcsin parenleftbigg a sin C c parenrightbigg 003 10.0 points A high fountain of water is located at the center of a circular pool as in the figure. A student walks around the pool and estimates its circumference to be 229 m. Next, the student stands at the edge of the pool and uses a protractor to gauge the angle of elevation of the top of the fountain to be 66 . 9 ◦ . How high is the fountain? Correct answer: 85 . 4477 m. Explanation: R h θ The circumference of the pool is C = 2 πR so its radius is R = C 2 π = 229 m 2 π = 36 . 4465 m The radius and the height of the fountain form...
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## This note was uploaded on 09/07/2010 for the course PHYS 1710 taught by Professor Weathers during the Fall '08 term at North Texas.

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Homework 3 Solutions - lim (kl9356) – Homework 3 –...

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