Homework 8 Solutions

Homework 8 Solutions - lim (kl9356) Homework 8 Weathers...

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Unformatted text preview: lim (kl9356) Homework 8 Weathers (17104) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points A force vector F = F x + F y acts on a particle that undergoes a displacement of vectors = s x + s y . Let: F x = 9 N, F y = 5 N, s x = 6 m, and s y = 2 m. Find the work done by the force on the particle. Correct answer: 44 J. Explanation: The work is given by W = vector F vectors = F x s x + F y s y = (9 N) (6 m) + ( 5 N) (2 m) = 44 J . 002 (part 2 of 2) 10.0 points Find the angle between vector F and vectors . Correct answer: 47 . 4896 . Explanation: Since W = vector F vectors = vextendsingle vextendsingle vextendsingle vector F vextendsingle vextendsingle vextendsingle | vectors | cos . The first and the third sides can be solved for to give = cos 1 W vextendsingle vextendsingle vextendsingle vector F vextendsingle vextendsingle vextendsingle | vectors | . First of all vextendsingle vextendsingle vextendsingle vector F vextendsingle vextendsingle vextendsingle = radicalBig F 2 x + F 2 y = radicalBig (9 N) 2 + ( 5 N) 2 = 10 . 2956 N and | vectors | = radicalBig s 2 x + s 2 y = radicalbig 6 m 2 + 2 m 2 = 6 . 32456 m . Thus = cos 1 bracketleftbigg 44 J (10 . 2956 N) (6 . 32456 m) bracketrightbigg = 47 . 4896 . 003 10.0 points A shopper in a supermarket pushes a cart with a force of 35 . 6 N directed at an angle of 23 . 4 downward from the horizontal. Find the work done by the shopper as she moves down a 51 . 6 m length of aisle....
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Homework 8 Solutions - lim (kl9356) Homework 8 Weathers...

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