Homework 19 Solutions

Homework 19 Solutions - lim (kl9356) – Homework 19 –...

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Unformatted text preview: lim (kl9356) – Homework 19 – Weathers – (22202) 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points The impedance from a to b in one of the cir- cuits below is plotted as a function of angular velocity ω . ω Impedance Select the circuit which gives rise to the above plot. 1. R C L b a 2. None of these 3. R C L b a 4. R C L b a 5. R C L b a 6. R C L b a cor- rect Explanation: Z parallel = 1 radicalBigg 1 R 2 + parenleftbigg 1 X C- 1 X L parenrightbigg 2 , Z series = radicalBig R 2 + ( X L- X C ) 2 , X C = 1 ω C , and X L = ω L. ====================== R C L b a Z LRC = 1 radicalBigg parenleftbigg R R 2 + X 2 C parenrightbigg 2 + parenleftbigg X C R 2 + X 2 C- 1 X L parenrightbigg 2 = R R 2 + parenleftbigg 1 ω C parenrightbigg 2 2 + 1 ω C R 2 + parenleftbigg 1 ω C parenrightbigg 2- 1 ω L 2 − 1 / 2 ω Impedance ω ω = 1 RC ====================== R C L b a Z CRL = 1 radicalBigg parenleftbigg R R 2 + X 2 L parenrightbigg 2 + parenleftbigg 1 X 2 C- X L R 2 + X 2 L parenrightbigg 2 = braceleftBigg bracketleftbigg R R 2 + ( ω L ) 2 bracketrightbigg 2 lim (kl9356) – Homework 19 – Weathers – (22202) 2 + bracketleftbigg ( ω C ) 2- ω L R 2 + ( ω L ) 2 bracketrightbigg 2 bracerightBigg − 1 / 2 ω Impedance ω ω = R L ====================== R C L b a Z RCL = R + 1 radicalBigg parenleftbigg 1 X C- 1 X L parenrightbigg 2 = R + bracketleftBigg parenleftbigg ω C- 1 ω L parenrightbigg 2 bracketrightBigg − 1 / 2 ω Impedance ω ω = 1 √ LC ====================== R C L b a Z RLC = radicalBig R 2 + ( X L- X C ) 2 = bracketleftBigg R 2 + parenleftbigg ω L- 1 ω C parenrightbigg 2 bracketrightBigg 1 / 2 ω Impedance ω ω = 1 √ LC ====================== R C L b a Z RLC = 1 radicalBigg 1 R 2 + parenleftbigg 1 X C- 1 X L parenrightbigg 2 = bracketleftBigg 1 R 2 + parenleftbigg ω C- 1 ω L parenrightbigg 2 bracketrightBigg − 1 / 2 ω Impedance ω ω = 1 √ LC keywords: 002 10.0 points A 15 Ω resistor, 13 mH inductor, and 86 μ F capacitor are connected in series to a 26 V (rms) source having variable frequency....
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This note was uploaded on 09/07/2010 for the course PHYS 2220 taught by Professor Littler during the Spring '00 term at North Texas.

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Homework 19 Solutions - lim (kl9356) – Homework 19 –...

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