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2000 Final Exam - 00C Exam Number 1101 1 3 4 5 Two thin...

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Unformatted text preview: 00C Exam Number 1101' 1. 3. 4. 5. Two thin concentric spherical conducting shells have radii of 0.5 m and 1.4 m. If the smaller shell has +75 uC of charge and the larger shell has ~125 uC of charge, determine the electric potential at a point 1.1 m from the center of the shells. ‘ (a) 3.35 x105 V (b) 1.00 x105 V (c) —5.10 x105 V (d) ~1.90 x105 V (e) ~1.57x 10 V Determine the electric potential at a point P located on the perpendicular central axis 3 .0 m from a uniform- ring of charge of radius 1.3 m and total charge 30 uC. a 8.26x104V (b) 1.11x10 V (c) 6.12x104V (d) 3.05x104V . (e) 4.55x104V 'A small object of mass 120 mg is observed to undergo an acceleration of magnitude 4.6 m/s2 when it is placed in a uniform electric field of magnitude 850 N/C. What is the charge on the object? (a) 445 nC (c) 849 nC (d) 1.23 ”C . (e) 1.91 MC A uniform electric field of strength E = 2.0 kN/C passes through a rectangular area 20 cm by 30 cm. The field makes an angle of 60° with the normal to the rectangle. Determine the electric flu’x'through the rectangle. - a 60.0 Nmz/C (b) 91.9 Nm /C (c) 109 Nmz/C (d) 31.1 NmZ/C (e) 120 NinZ/C Find the equivalent capacitance between points a and b in the combination of capacitors shown in the figure. Each capacitor has a capacitance of 55 pF. (a) 39.2 pF (b) 62.5 pF n»... (e) 175 pF MO! '10. A spherical balloon of radius r = 20 cm carries a charge uniformly distributed over its surface with surface charge density 9.00 nC/inz. What is the electric field at a distance of 50 cm from the center of the balloon? Suppose that the balloon shrinks to a radius of 10 em but loses none of its charge. What is the field at the same distance r = 50 cm from its center?: 1.631053. % 0,. 7% 7,. Wk was Calculate the amount of work required to assemble point charges at three of the corners of a square 15 cm on a side. The two charges brought to diagonally opposite corners are 5.0 uC each, and the charge placed diagonally opposite the empty corner is ~16 itC. Assume that before assembly the charges are infinitely separated from each other. W = _ 8.53 3' A charge 2g is placed inside a cylinder at the midpoint of the cylinder’s axis. The flux through one end of the cylinder is (1),. Obtain an equation for the flux through the curved part of the cylinder’s surface in terms of q and (131. Shaun = 26% ~ 2 (y The plates of a parallel plate capacitor are separated by 0.01 mm. When this capacitor is charged such that the magnitude of the surface charge density on the plates is 25 nC/cmz, the magnitude of the total charge on each plate is 3.0 pC. What would be the capacitance of a device identical to this in all respects except having the volume between the plates filled with a dielectric of constant K = 2.5? ‘ CI: 26.6 “F An air—filled coaxial cylindrical capacitor has a length of 10.0 m. The inner conductor has a radius of 5.0 mm and the outer conductor has a radius of 10.0 mm. If the magnitude of the charge per unit length on each conductor is 15 nC/m, how much energy is stored in the capacitor? 8= WOLF FMS 2220 2000C ASSW V‘D @ r=00- [15¢ SW?O$HF¢M ?rim?6)!¢2 add 7:6wa dw- +0 €406. Sfllere; CAM-g1. The. 130191601 dMe'fn Hie inner Sphere 41 r’a 1'5 €$u0ValM {615111 091 PM Chi/fie 0a loaded ”‘1 M? 5‘191'4’15‘S coda! (mwdsvmmdvy). The Yamaha! due ’[0 ML coder sfkeve '1: WW 5v V<b,avw“s earn! 41, m We of mo, who) «fig/m 2:, 21mm 1:: flu! of a Few! emf 62,, [W44 «1 +4. sfzm': Cevfl‘er. D. keQ ' I. y ”‘> V0): 359‘ * "[9 wkm ke=8.%9xlo°Nm/C o‘r‘la )4st V=0 @rmo. Inieaarwle om‘tkc 'Fafwfial due‘fo cachincrmm (J CW d0 mffiz final [MG 610 Q V=§7=0 50.20%???“ ”E? 5 c . ‘— fl ~=> {3% *“EL "*0“ \c c Cw c .3.— _ - a 5 CA: 'é’+"é =% CC¢_,C+C+ CA 1C Q 3mm 0? we), we elem mu M5244: MW .05 WW MAM“: f0 a w CAM-7e Q [what 0:110.» water of f6; Jawllam: f” v4 ,. .3 \ U62, Gaus'slmu éE‘dA = 121%“: alum? MIarficcr/{l Mlleqmim “ID 114 a Q 534‘“? §mdm5 r>°n 6%de W111!- W100“. s; w 0 000 00-: 2% 0 0+) 1-F-fiu. baucm Shrinks, ’du SVMM'G) 0‘: Winch/M ‘1: mafeol‘ed/ 04ml {Li M wow MW 'Magmhm is m saw. 7W’ch E is M54.“ a4 inflw lsfcug.‘ 0%. 0-. “‘ W= 50.0.2.0 E31831. We 61.0w) “4&0 Tu. L...)- $>W=q0i0+fi0g+0s~1=~<0%) 8‘ USe Gauss's Law - @Ema E gEMA = 124?“; . . m 45:” MM» calm“! 5W: Wm memo at”! mfribufim—Eww‘i, M 41¢! Cngj SM“, 0'!“ ”WARM WVW'MCWCJSWQ : Qbmm‘ 23h“ éCuwc => (Pom; (baht-24>“ = 3-243“ 9. for M alr'findqm’rafld 13/019 @104th , C: .135 “(£131. A 13%: am: amJ db fie labia Wm “to M: m , 5M ma 1m desk-mm «f armada“: (1134 Raw Thule equaling AV’EA WW FMAE Maid-20262165 :3 gwmég E=go§=égg =3> 4V=Qd ‘-'>C‘€D’é xnmswum. ohm M! om} 3; W» A.- 09;, F» m Mammal cow-m. c’= KC I 69 (O. Innu- cmabwlw mam m ' haw: L Negfioted emaa‘s. Ouier candudw realm - b mum swiutk; “WW .3 g—f:%[email protected])1= 5%: ”Nu chug; QWHUCa/fuc'rkv is (bivca L7 Gnu. Mm ,2 hm humwdwdy (111m? MJKMEW. “flu Wm emu L’wl from flu dzfiw’flm Japamu, C= 37‘ ml mlscmmfémx's law. Chm asylum/rial] Gamma sulfau minimum V'"‘(0L4Y"lo) 04w! flaw/m L, "I!“ WSW am 614 7% Winders. oil-mum Ea‘a gE-RM =§EfiA M = 5% = 5,-2an Mal M CUM/d SIM/nu SMvu. AL a 2kg -> (IL .‘ 5 ———' ._, : ~-—-—— : We’ “raw §E~MA= 1%“: .2: 2: .-:>-2nthr 6., "> E.— Ere“ v. b 5 :W b 12. '___>_ AV5'SErd" :Jl’ira’id” :“2k‘RL—F = 32kt}, Qua a ='2ke)>£«a \L L $ : [—9 = I 5 .———-—.—~ C -;.v MM: 2w; , (20‘ , 2 .b. » Ezémg' keR-Lvflfl.“ ...
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