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Unformatted text preview: = 1 0 0 0 1 0 0 0 1 has a pivot in the last column. 1 (c) No value of h will make the vectors linearly independent. 5. (a) T fails (i) because " 2 2 # = T " 1 2 #! = T " 1 1 # + " 1 #! 6 = T " 1 1 #! + T " 1 #! = " 1 1 # + " 1 # = " 1 2 # T fails (ii) because " 11 # = T "11 #! 6 = (1) T " 1 1 #! = (1) " 1 1 # = "11 # (b) YES, T is onto. (c) "7 22 # 6. (a) 2 2 (b) NO, because all vectors in Col(A) have zero last component. (c) NO, because A 32 1 = 18 , which is not a zero vector. (d) 3 21 2...
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This note was uploaded on 09/08/2010 for the course MATH 129A at San Jose State University .
 '10
 So,Wasin
 Linear Algebra, Algebra

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