# CH06suphw - S6.7 X= 156.9 + 153.2 + 153.6 + 155.5 + 156.6 =...

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S6.7 156.9 153.2 153.6 155.5 156.6 155.16 mm 5 4.2 4.6 4.1 5.0 4.5 4.48 mm 5 X R ++++ == X -chart: 2 2 155.16 mm from the sample data UCL 155.16 (0.308 4.48) 156.54 mm LCL 155.16 (0.308 4.48) 153.78 mm. x x X XA R R = =+ = + × = =− = × = R -chart: R4 R3 4.48 mm UCL 1.777(4.48) 7.96 mm LCL .223(4.48) 1.00 mm R DR = = = ( Note : The mean of a process for 155 mm pistons should be 155 mm, not 155.16 mm. An investigation should take place to find the discrepancy and correct it.) S6.10 10, 3.3 XR (a) Population standard deviation = 1.36, 1.36 5 0.61 x σ (b) Using x ( ) () 10 3 0.61 11.83 10 3 0.61 8.17 UCL LCL = = Using A 2 = 0.577 ( ) 10 3.3 0.577 11.90 10 3.3 0.577 8.10 UCL LCL = = (c) UCL = 2.115(3.3) = 6.98 LCL = 0(3.3) = 0 (d) Yes, both mean and range charts indicate process is in control. S6.15 (a) The total number defective is 57. 57/1,000 0.057 (0.057)(0.943) 0.0005375 0.023 100 UCL 0.057 3(0.023) 0.057 0.069 0.126 ˆ LCL 0.057 3(0.023) 0.057 0.069 0.012 0 ˆ p p p p = =+= =−= −= (b) The process is out of control on the third day (of the next 3 days).

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S6.23 213/ 5 42.6 test errors per school
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## This note was uploaded on 09/08/2010 for the course BUS 140 at San Jose State University .

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CH06suphw - S6.7 X= 156.9 + 153.2 + 153.6 + 155.5 + 156.6 =...

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