Homework 9 key - CEE 122 Traffic Engineering Spring 2010 Homework#9 Due 1 Key a 3 second rule h=3 q=1/h=1*3600/3=1200 veh/hr independent of k u q m

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CEE 122 Traffic Engineering Spring 2010 Homework #9 Due: __________________ 1. Key: a) 3 second rule, h=3 q=1/h=1*3600/3=1200 veh/hr, independent of k & u hr veh q m / 1200 = For u-q curve, q=1200 veh/hr @ u=0, and q=1200 veh/hr @ u=75 For q-k curve, q=1200 veh/hr @ k=0, and q=1200 veh/hr @ k=150 u-q 0 10 20 30 40 50 60 70 0 200 400 600 800 1000 1200 1400 q u q-k 0 200 400 600 800 1000 1200 1400 05 0 1 0 0 1 5 0 k q b) 10 mile-per-hour rule () L u u ku q L u s k L u L L u s + = = + = = + = + = 10 10 10 10 1 10 10 10
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Limit u , () hr veh L L u L u u q m / 2640 5280 20 10 0 1 10 10 1 10 10 10 = = + = + = + = For u-q curve, L u u ku q + = = 10 10 q=0 veh/hr @ u=0, and q=2330 veh/hr @ u=75. u-q 0 10 20 30 40 50 60 70 0 500 1000 1500 2000 2500 q u q-k 0 500 1000 1500 2000 2500 3000 05 0 1 0 0 1 5 0 k q For q-k curve, = = = + + = = 1 1 10 10 10 10 10 10 10 1 L k L k u k L u L u s k k L L k k ku q 10 10 1 1 10 = = = q=2640 veh/hr @ k=0, and q=1140 veh/hr @ k=150
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2. Key: a) Queuing diagram Cumulative Vehicle - Time 0 2000 4000 6000 8000 10000 12000 14000 16000 18000 20000 6:00 AM 7:00 AM 8:00 AM 9:00 AM 10:00 AM 11:00 AM Time Cumulative Vehicle Cumulative Demand Capacity b)
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This note was uploaded on 09/08/2010 for the course CE 224 at San Jose State University .

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Homework 9 key - CEE 122 Traffic Engineering Spring 2010 Homework#9 Due 1 Key a 3 second rule h=3 q=1/h=1*3600/3=1200 veh/hr independent of k u q m

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