129a_ans2 - Spring 2010 Answer of HW2 -4 1.5 #6 x = x3 3 1...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Spring 2010 Answer of HW2 1.5 #6 x = x 3 - 4 3 1 1.5 #12 x = x 2 - 5 1 0 0 0 0 + x 3 - 8 0 7 1 0 0 + x 4 - 1 0 - 4 0 1 0 1.5 #13 x = 5 - 2 0 + x 3 4 - 7 1 . Geometrically, it is the line through 5 - 2 0 and parallel to 4 - 7 1 . 1.5 #35 A = 1 - 2 1 2 - 3 1 0 - 1 1 1.5 #38 No. If Ax = y does not have a solution, then A cannot have a pivot in each row.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 09/08/2010 for the course MATH 129A at San Jose State University .

Ask a homework question - tutors are online