key_ch10review_sp10 - Answers to even recommended problems...

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Answers to even recommended problems from Chapter 10 Review #4 : (a) 11 i 4 j k (b) 14 (c) 1 (d) < 3 , 7 , 5> (e) 3 35 (f) 18 (g) 0 (h) 33 i 21 j 6 k (i) comp a b = a b a =− 1 6 (j) proj a b = a b a 2 a =− 1 6 i j 2 k (k) 96 o #6: Let a = j + 2 k and b = i – 2 j + 3 k . The two unit vectors are given by ± a × b a × b 1 3 6 7 i 2 j k #10: The volume is given by the absolute value of the scalar triple product: AB ⋅ AC × AD ∣= 6 #12: The displacement vector between the two points is D = < 4,3,6 > , thus the work is W = F D = 87J #18: Since the plane is parallel to x + 4 y – 3 z =1, it must have the same normal vector n = <1, 4, -3>. Hence the equation is ( x – 2) + 4( y – 1) –3 z = 0. Simplifying gives x + 4 y – 3 z = 6. #20:
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This note was uploaded on 09/08/2010 for the course MATH 112 at San Jose State University .

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key_ch10review_sp10 - Answers to even recommended problems...

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