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Unformatted text preview: Answers to EvenNumbered HW  Test 2 HW #7  13 HW 7 p. 96 2. lim x → 1 f ( x ) = 3 means we can make f ( x ) as close to 3 as we like by taking x sufficiently close to 1 from the left, but not equal to 1. lim x → 1+ f ( x ) = 7 means we can make f ( x ) as close to 7 as we like by taking x sufficiently close to 1 from the right, but not equal to 1. The (twosided) limit lim x → 1 f ( x ) does not exist (DNE) since the left hand limit is not equal to the righthand limit. 4. (a) 2; (b) 4; (c) 2; (d) DNE; (3) 3. 6. (a) 4; (b) 4; (c) 4; (d) undefined; (e) 1; (f) 1; (g) DNE; (h) 1; (i) 2; (j) undefined; (k) 3; (l) DNE; this is because we can’t make f ( x ) as close as we like to some number L by taking x sufficiently close to 5 from the left, but not equal to 5. A reasonable guess for L would be 4, but if we want f ( x ) within 0.5 of 4, you can see no matter how close we make x to 5 from the left, some values of f ( x ) will always overshoot the range (3 . 5 , 4 . 5). 8. (a)∞ ; (b) ∞ ; (c)∞ ; (d) ∞ ; (e) x = 3; x = 2; x = 5. 14. There are many correct answers. Just draw little sections of the graph with each one satisfying a stated condition. You don’t even have to connect up the different sections, although that would give a more typicallooking function. 26. To see that this is an infinite limit, just substitute 3 in the numerator and denominator: 1 is infinite. To get the right sign, substitute a value of x slightly to the left of 3. The denominator will be negative, and the numerator will be close to 1. The two negatives give (positive) ∞ ....
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This note was uploaded on 09/08/2010 for the course MATH 30 at San Jose State University .
 '10
 Vartanian,Michael

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