S09 Midterm 1 - Name ID Chem 1303 Midterm 1 Chem 130C...

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Name ID # Chem 1303 Midterm 1 Spring 2009 Chem 130C, Midterm1 1. a) ( 7 points ) Sequencing of the 100Mb genome of the nematode C. elegans showed its composition to be 36% (G+C) and 64% (A+T). The recognition/cleavage site of the restriction endonuclease Hind III is the palindromic sequence AAGCTT. Approximately how many Hind III sites does the C. elegans genome contain? b) ( 6 points ) The human genome comprises a total of 6.4 × 10 9 nucleotides on 46 chromosomes. What would be the minimum number of origins required to replicate the human genome in the 8-hour S phase of the cell cycle if DNA polymerase incorporates 50 nucleotides per second into the growing chains? c) ( 7 points ) The genome of E. coli contains 4.6 × 10 6 base pairs (bps). What weight of glucose would have to be consumed in order to fuel one round of replication of the E. coli DNA? (The molecular weight of glucose is 180; the oxidation of one glucose molecule yields about 30 ATPs; N AV = 6.2 x 10 23 )
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Chem 130C Midterm 1
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S09 Midterm 1 - Name ID Chem 1303 Midterm 1 Chem 130C...

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