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distributed uniformly over both sides of the original plate, with half being on the side
near the field point. Thus,
6
42
2
6.0 10 C
4.69 10 C/m .
2
2(0.080 m)
q
A
σ
−
−
×
==
=
×
The magnitude of the field is
42
7
12
2
2
0
4.69 10 C/m
5.3 10 N/C.
8.85 10
C / N m
E
σ
ε
−
×
==
=×
×⋅
The field is normal to the plate and since the charge on the plate is positive, it points
away from the plate.
(b) At a point far away from the plate, the electric field is nearly that of a point particle
with charge equal to the total charge on the plate. The magnitude of the field is
22
0
/4
/
Eq
r k
qr
πε
==
, where
r
is the distance from the plate. Thus,
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This note was uploaded on 09/07/2010 for the course PHYS 247 taught by Professor Zv during the Fall '10 term at The Petroleum Institute.
 Fall '10
 ZV
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