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Eforce-4 - Net force on q3 is to the left and its magnitude...

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Two point charges are located on the x-axis. One charge, q1=-10.0 nC, is located at -1.50 m. The second charge, q2=40.0 nC is at the origin (x = 0). What is the net force exerted by these two charges on a third charge q3=50.0 nC placed between q1 and q2 at x3=-1.10 m? Use 8.85 x10 ^-12 Nm^2/C^2 for the permittivity of free space. Force between 1 and 3 is attractive ( So, this force is to the left on charge q3). Force between 2 and 3 is repulsive ( So, this force is to the left on charge q3 as well).
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Unformatted text preview: Net force on q3 is to the left and its magnitude is the sum of the magnitudes of the two forces F13 and F23. F13 = k q1 q3/0.4^2 F23 = k q2 q3 / 1.1^2 Net force on q3 = F13 + F23 = k q1 q3/0.4^2 + k q2 q3 / 1.1^2 where k = 8.85 x10 ^-12 Nm^2/C^2 Net force on q3 = k (q1 q3/0.4^2 + q2 q3 / 1.1^2) Net force on q3 = 8.85 x10 -12 (10x10-9 x 50x10-9 /0.4^2 + 40x10-9 x 50x10-9 / 1.1^2) Net force on q3 = 8.85 x10 -12 (10x50 /0.4^2 + 40x50 / 1.1^2) x 10-18 Net force on q3 = 4.2 x 10-26 N...
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