This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: intensity of their colors at the time. 2. Arrange the four hydrocarbons in order of their reactivity toward bromine, most reactive first, and compare your results with your predictions. Write a balanced equation for each reaction and give structures for each free radical intermediate. Arrange the free radicals in order of stability and explain their relative stabilities. Write a complete mechanism for the bromination of toluene. Data and Observations: 1) Isopropyl Benzene immediately cleared 2) ethylbenzene a minute or so, yellowish 3) Toluene Several minutes light orange 4) Tertbutyl - not decolorized orange Conclusion: Our results of the most reactive begin with isopropyl benzene, continue with ethylbenzene, toluene, and finally tertiary butyl. This reactivity order can be explained by these hydrocarbons reactivity with free radical bromination. The first 3 occur at the benzylic position with the more alkyl groups meaning more electron donating plausibility. 2...
View Full Document
This note was uploaded on 09/07/2010 for the course CHEM CH 2123 taught by Professor Heemoonpark during the Summer '10 term at Austin Community College.
- Summer '10