discussion - decrease, therefore delta t decreases. b) The...

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Sam Lancaster 10/23/09 Discussion For parts A and B of experiment 7, the first step we set an ice bath and test tube holder, in order to first find the freezing point of pure water and a solution of water with an unknown. A CBL2/TI temperature probe was used recording the temperature on intervals of 15 seconds all the way until 450 seconds. We used this method and found that the freezing point of pure water is -0.1 ° C. next we added approximately .5 g of an unknown solution to 10 mL of water in a test tube. We repeateded the steps used in part A and found this solutions freezing point to be -0.6 ° C. an error that we might have encountered is that the data collection may have been started too soon, and the solution would not reach freezing point. Topic 1 a) Since delta t is proportional to molality and molality decreases when the moles
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Unformatted text preview: decrease, therefore delta t decreases. b) The molar mass will be smaller because the molality will be smaller. Topic 2 a) The one that doesn’t ionize with water because the one that does ionize has a Van’t Hoff correction factor while the other does not. Topic 3 a) Because molarity uses volume of solution which is temperature dependant, while molality uses kilograms of solvent which is not temperature dependant. Topic 4 a) the supercooling region is where it gets so cold that it freezes. Topic 5 a) Because vapor pressures are known at certain temperatures, and the moles of the components are known, Raoult’s law can be used to find the vapor pressure of the solution...
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This note was uploaded on 09/07/2010 for the course CHEMISTRY 2200 taught by Professor Dr.rikitiktavi during the Spring '10 term at GCTS - Charlotte.

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