Unformatted text preview: You plug the solutions a and b into: (x-a)(x-b) = 0 If you multiply a quadratic equation by a contant number, you do not change the solutions. So x^2 = 3 and 2x^2 = 6 have the same solutions. Find a quadratic equation that has roots x = 2 and x = 5: (x-2)(x-5) = 0. Find a quadratic equation that has two roots at x = 1: (x-1)(x-1) = 0....
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This note was uploaded on 09/08/2010 for the course HCA MAT 117 taught by Professor Barnes during the Spring '10 term at University of Phoenix.
- Spring '10