Unformatted text preview: You plug the solutions a and b into: (xa)(xb) = 0 If you multiply a quadratic equation by a contant number, you do not change the solutions. So x^2 = 3 and 2x^2 = 6 have the same solutions. Find a quadratic equation that has roots x = 2 and x = 5: (x2)(x5) = 0. Find a quadratic equation that has two roots at x = 1: (x1)(x1) = 0....
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 Spring '10
 barnes
 Quadratic equation

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