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315 HW_6

# 315 HW_6 - 6 θ = F t J ¨ θ k‘ 6 17 k‘ 2 36 θ = F t...

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North Carolina State University Department of Mechanical and Aerospace Engineering MAE 315-1 Dynamics of Machines Summer I, 2009 Homework #6: Due date June 17, 2010 Rao’s Textbook problems: 5.28, 5.29, 5.34, 5.41, 5.48, 5.49, 5.57. Answers: 5.28: ω 1 = 0 . 5176 q k t 1 J 0 2 = 1 . 9319 q k t 1 J 0 r 1 = 1 . 3661 ,r 2 = - 0 . 3661. 5.29: ω 2 1 2 2 = k 2 2 m + k 1 + k 2 m o r k 2 2 m + k 1 + k 2 m o · 2 - 2 k 1 k 2 mm o . 5.34: ω 1 = 0 . 5904 q k m 2 = 1 . 4668 q k m . 5.41: m ¨ x + 3 kx + k‘
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Unformatted text preview: 6 θ = F ( t ) J ¨ θ + k‘ 6 + 17 k‘ 2 36 θ = F ( t ) ‘ 3 where J = m‘ 2 12 . 5.48: X 1 =-(40 . 004 + 0 . 0192 j ) × 10-4 in,X 2 = (0 . 922 + 0 . 295 j ) × 10-4 in . 5.49: k 2 m 2 = ω 2 . 5.57: ω 1 = 0 ,ω 2 = q m 1 k + m 2 k + kJ o /r 2 m 1 m 2 + m 1 J /r 2 . 1...
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• Summer '08
• WU
• University of North Carolina at Chapel Hill, North Carolina State University, Mechanical and Aerospace Engineering, 0.0192j, 0.295j

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