Ch11 - = 197 ft 11.33 y = 0.645 ft y = 4.30 ft 11.35 5 1 2 2 2 ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ = g z Q y c 11.37 Q = 3.24 ft 3/s 11.39 y 2 = 0.610

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Introduction to Fluid Mechanics 7 th Edition Fox, Pritchard, & McDonald Answers to Selected Problems, Chapter 11 11.1 Q = 3.18 m 3 /s 11.3 y = 2.61 ft 11.5 y 2 = 0.507 m Fr 2 = 2.51 11.7 S 0 = 0.00186 11.9 S 0 = 0.00160 11.11 Q = 0.194 m 3 /s 11.13 y = 2.47 ft 11.15 y = 0.775 m 11.19 y = 4.83 ft V = 3.69 ft/s 11.23 y = 7.38 ft 11.25 y c = 0.365 ft, E c = 0.547 ft y c = 0.759 ft, E c = 1.14 ft y c = 1.067 ft, E c = 1.60 ft y c = 1.46 ft, E c = 2.19 ft 11.27 y c = 0.637 m 11.31 Δ x
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Unformatted text preview: = 197 ft 11.33 y = 0.645 ft y = 4.30 ft 11.35 5 1 2 2 2 ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ = g z Q y c 11.37 Q = 3.24 ft 3 /s 11.39 y 2 = 0.610 ft (– 32.2%) 11.41 y 2 = 1.31 ft 11.43 Q = 49.5 ft 3 /s 11.45 Q = 10.6 m 3 /s y c = 0.894 m H l = 0.808 m 11.47 y 2 = 5.94 ft 11.49 Q = 54.0 ft 3 /s H l = 1.62 ft 11.51 y 2 = 4.45 m H l = 9.31 m 11.53 Q = 26.6 ft 3 /s 11.55 H = 0.514 m 11.57 C w = 1.45...
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This note was uploaded on 09/08/2010 for the course AME 331 taught by Professor Zohar during the Spring '08 term at University of Arizona- Tucson.

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