Quiz5 - Fall 2010 7B Quiz 5 Exp. Change (last) RubricCode:...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
A = A o e ± t τ , PE C = 1 2 CV 2 , I = Q t , I A = I B [ ] , R S = R 1 + R 2 +... [ ] , 1 R P = 1 R 1 + 1 R 2 +... , R P = R 1 R 2 R 1 + R 2 V R = IR [ ] , Sum of Voltage changes around loop = 0 , Q C = CV [ ] , C = κε 0 A d , C P = C 1 + C 2 +... [ ] , 1 C S = 1 C 1 + 1 C 2 +... Rubric Code: a) The lipid bilayer of the cell separates charge concentrations that are built up either though passive ion channels that allows the flow of ions due to concentration differences, or active pumps that use energy to push the ion’s against the potential difference. If the membrane potential is 60mV and the charge on either side is 6x10 -9 C, find the capacitance of the
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 09/08/2010 for the course PHY 7B PHY7B taught by Professor Cebra during the Winter '10 term at UC Davis.

Ask a homework question - tutors are online