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ExtraPracticeProblemsSolutions

# ExtraPracticeProblemsSolutions - Extra Practice Problems...

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Extra Practice Problems Solutions 1) a) Because the magnetic field magnitude is changing at a constant rate between t = 0 s and t = 60 s, the magnetic flux is also changing at a constant rate between these times. Between t = 60 s and t = 120 s, the magnetic flux is not changing. Therefore the graph of current vs. time should look like b) In this case, the magnetic field is pointing to the left so none of the magnetic field lines are going through the loop. Therefore, the flux in this case is always zero and never changing. The current is thus zero for all times between t = 0 and t = 120 seconds. 2) a) The light bulb will be lit between times 1 and 2 and between times 3 and 4 but not between times 2 and 3. b) The change in velocity will not change the answer to part a). The light bulb will still be lit between times 1 and 2 and between times 3 and 4 but not between times 2 and 3. The situation will change, however, due to the fact that when the flux is changing (between

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ExtraPracticeProblemsSolutions - Extra Practice Problems...

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