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Unformatted text preview: Therefore, because p=h/ λ , its wavelength decreases. 2) Since both atoms are trapped in the same size region and in their lowest energy state, we know they both have wavelengths of λ =2L=2x10-6 . This means they must also have the same momentum p=h/ λ . Since KE=p 2 /2m, XE will have a lower KE as it has the larger mass....
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This note was uploaded on 09/08/2010 for the course PHY7C 7C taught by Professor Neal/james during the Spring '10 term at UC Davis.
- Spring '10