Unformatted text preview: + b = 0. The roots of this equation are: m 1 =  a/2 + 1/2x(a 2 4b) 1/2 =  10/2 + 1/2 x(10 2 4 x 66.67) 1/2 = 5 + 6.46 i, and m 2 = a/2  1/2x(a 2 – 4b) 1/2 =  10/2  1/2x(10 2 4x66.67) 1/2 =  5 – 6.46 i. So, the general solution can be expressed as y(t) = e5t x [ A Sin {6.46t} + B Cos (6.46t) ], where natural frequency of oscillation of the system is ω o = 6.46 rad/sec. Would need two initial conditions to solve for the constants A and B. (c) The time between two consecutive peaks is simply, ∆ t = 1/f = 1/( ω o /2 π ) = 2 π / ω o = 2 π /6.46 = 0.973 sec . C m K y(t)...
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This note was uploaded on 09/08/2010 for the course ME 130 at San Jose State.
 '08
 Saxena,Dr.

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