Exam 2-solutions-1 - Version 055 Exam 2 seckin (57195) 1...

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Unformatted text preview: Version 055 Exam 2 seckin (57195) 1 This print-out should have 19 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points When the graph of f is 2 4 6 8 10 2 4 6 2 4 6 2 4 6 which of the following is the graph of f ? 1. 4 8 4 4 4 correct 2. 4 8 4 4 4 3. 4 8 4 4 4 4. 4 8 4 4 4 5. 4 8 4 4 4 Explanation: The graph of f has exactly one point at which it changes concavity, so the graph of f has exactly one x-intercept. This rules out the parabola. But the graph of f changes concavity at x = 2, so the graph of f must be one of the straight lines having x = 2 as x-intercept. This rules out two of the lines, leaving just two lines each with the same x- intercept but slopes of opposite sign. An inspection of the concavity of the graph of f to the left and right of x = 2 thus shows that Version 055 Exam 2 seckin (57195) 2 2 4 6 8 10 2 4 6 2 4 6 2 4 6 must be the graph of f . 002 10.0 points Find the equation of the tangent line to the graph of f ( x ) = (6 x + 10) 1 4 at the point P = (1 , f (1)) on the graph of f . 1. y = 6 x + 29 16 2. y = 6 x + 59 3. y + 3 16 x = 29 16 4. y = 3 16 x + 29 16 correct 5. y + 6 x = 59 6. y = 3 16 x + 59 Explanation: When x = 1 the corresponding value of f is f (1) = 2, so P = (1 , 2). On the other hand, by the Power rule, f ( x ) = 3 2 (6 x + 10) 3 4 . Consequently, the slope of the tangent line at P is given by f (1) = 3 2(16) 3 4 = 3 16 , so by the point slope formula, the equation of the tangent line at P is y 2 = 3 16 ( x 1) . After simplification this becomes y = 3 16 x + 29 16 . 003 10.0 points Determine f ( x ) when f ( x ) = x 2 x 2 1 . 1. f ( x ) = 2 x 1 ( x 2 1) 1 / 2 2. f ( x ) = 1 2 x ( x 2 1) 3 / 2 3. f ( x ) = 2 x 1 ( x 2 1) 3 / 2 correct 4. f ( x ) = 1 2 x ( x 2 1) 1 / 2 5. f ( x ) = 1 + 2 x ( x 2 1) 1 / 2 6. f ( x ) = 1 + 2 x ( x 2 1) 3 / 2 Explanation: By the Product and Chain Rules, f ( x ) = 1 ( x 2 1) 1 / 2 2 x ( x 2) 2( x 2 1) 3 / 2 = ( x 2 1) x ( x 2) ( x 2 1) 3 / 2 . Consequently, f ( x ) = 2 x 1 ( x 2 1) 3 / 2 . Version 055 Exam 2 seckin (57195) 3 (Note: the Quotient Rule could have been used, but its simpler to use the Product Rule.) keywords: derivative, square root, chain rule, product rule 004 10.0 points Find the second derivative of f when f ( x ) = 4 cos 2 x 3 cos 2 x . 1. f ( x ) = 22 sin 2 x 2. f ( x ) = 22 cos 2 x correct 3. f ( x ) = 11 sin 2 x 4. f ( x ) = 22 sin2 x 5. f ( x ) = 11 cos 2 x 6. f ( x ) = 22 cos 2 x Explanation: Differentiating once we see that f ( x ) = 8 sin2 x + 6 sin x cos x ....
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Exam 2-solutions-1 - Version 055 Exam 2 seckin (57195) 1...

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