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Unformatted text preview: vo (ytv59) homework 03 Turner (56705) 1 This printout should have 11 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 10.0 points The diagram shows an isolated, positive charge Q , where point B is twice as far away from Q as point A . + Q A B 10 cm 20 cm The ratio of the electric field strength at point A to the electric field strength at point B is 1. E A E B = 2 1 . 2. E A E B = 4 1 . correct 3. E A E B = 1 2 . 4. E A E B = 8 1 . 5. E A E B = 1 1 . Explanation: Let : r B = 2 r A . The electric field strength E 1 r 2 , so E A E B = 1 r 2 A 1 r 2 B = r 2 B r 2 A = (2 r ) 2 r 2 = 4 . 002 (part 1 of 3) 10.0 points Consider the setup shown in the figure be low, where the arc is a semicircle with radius r . The total charge Q is negative, and dis tributed uniformly on the semicircle. The charge on a small segment with angle is labeled q . x y r x y I II III IV B A O q is given by 1. q = 2 Q 2. q = Q 3. q = 2 Q 4. q = Q 5. q = Q 2 6. q = Q 2 7. None of these 8. q = Q 9. q = 2 Q 10. q = Q correct Explanation: The angle of a semicircle is , thus the charge on a small segment with angle is q = Q . 003 (part 2 of 3) 10.0 points The magnitude of the xcomponent of the electric field at the center, due to q , is given by 1. E x = k  q  cos r 2 correct 2. E x = k  q  (sin ) r 2 3. E x = k  q  (cos ) r 2 vo (ytv59) homework 03 Turner (56705) 2 4. E x = k  q  r 2 5. E x = k  q  (sin ) r 6. E x = k  q  sin r 2 7. E x = k  q  cos r 8. E x = k  q...
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This note was uploaded on 09/12/2010 for the course PHY 303L taught by Professor Turner during the Fall '10 term at Austin Community College.
 Fall '10
 turner
 Charge, Work

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