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old hw8 - Copy

# old hw8 - Copy - vo(ytv59 oldhomework 08 Turner(56705 This...

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vo (ytv59) – oldhomework 08 – Turner – (56705) 1 This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 4) 10.0 points Two charges are located in the ( x,y ) plane as shown in the figure below. The fields pro- duced by these charges are observed at the origin, p = (0 , 0). The Coulomb constant is 8 . 98755 × 10 9 N · m 2 / C 2 . x y + Q + Q p b a a Use Coulomb’s law to find the x -component of the electric field at p . 1. E x = 2 k e Q a 2 + b 2 2. E x = - k e Qa ( a 2 + b 2 ) 3 / 2 3. E x = - 4 k e Qa ( a 2 + b 2 ) 3 / 2 4. E x = 0 5. E x = 2 k e Qa ( a 2 + b 2 ) 3 / 2 6. E x = k e Qa ( a 2 + b 2 ) 3 / 2 7. E x = 4 k e Qa ( a 2 + b 2 ) 3 / 2 8. E x = - 2 k e Qa ( a 2 + b 2 ) 3 / 2 9. E x = - 2 k e Q a 2 + b 2 002 (part 2 of 4) 10.0 points Let: V = 0 at infinity. Find the electric potential at p. 1. V y = 2 k e Qa a 2 + b 2 2. V y = + 2 k e Q a 2 + b 2 3. V y = 4 k e Qa a 2 + b 2 4. V y = - 2 k e Qa a 2 + b 2 5. V y = 4 k e Q a 2 + b 2 6. V y = - 4 k e Q a 2 + b 2 7. V y = - 4 k e Qa a 2 + b 2 8. V y = 0 9. V y = - 2 k e Q a 2 + b 2 003 (part 3 of 4) 10.0 points Find the y -component of the electric field at p. 1. E y = + 4 k e Qb ( a 2 + b 2 ) 3 / 2 2. E y = + 2 k e Q a 2 + b 2 3. E y = - 4 k e Qb ( a 2 + b 2 ) 3 / 2 4. E y = + 2 k e Qb ( a 2 + b 2 ) 3 / 2 5. E y = + k e Qb ( a 2 + b 2 ) 3 / 2 6. E y = - 2 k e Q a 2 + b 2 7. E y = - k e Qb ( a 2 + b 2 ) 3 / 2 8. E y = 0 9. E y = - 2 k e Qb ( a 2 + b 2 ) 3 / 2 004 (part 4 of 4) 10.0 points Point p is the origin (0 , 0) and point s is at (0 ,s ). Find V (0 , 0) - V (0 ,s ) [ e.g. , ( V p - V s )]. 1. V p - V s = 2 k e Q a 2 + b 2 - 2 k e Q radicalbig a 2 + ( s + b ) 2

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vo (ytv59) – oldhomework 08 – Turner – (56705) 2 2. V p - V s = 4 k e Q radicalbig a 2 + ( s + b ) 2 3. V p - V s = 2 k e Q a 2 + b 2 - 2 k e Q a 2 + ( s + b ) 2 4. V
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