CHAPTER 45 - 1

CHAPTER 45 - 1 - CHAPTER 45 Astrophysics and Cosmology...

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Unformatted text preview: CHAPTER 45 Astrophysics and Cosmology Note: A factor that appears in the analysis of energies is e 2 /4p = (1.60 10 19 C) 2 /4p(8.85 10 12 C 2 /N m 2 ) = 2.30 10 28 J m = 1.44 MeV fm. 1. Using the definition of the parsec, we find the equivalent distance in m: D = d / ; 1 pc = (1.50 10 11 m)/[(1.000 )/(3600 /)(180/p rad)] = 3.094 10 16 m. From the definition of the light-year, we have 1 pc = (3.094 10 16 m)/(3.00 10 8 m/s)(3.16 10 7 s/yr) = 3.26 ly. 2. We find the distance from D = 1/ = [1/(0.38 )](3.26 ly/pc) = 8.6 ly . 3. We find the distance from D = 1/ = [1/(0.00019)(3600 /)](3.26 ly/pc) = 4.8 ly . 4. ( a ) We find the parallax angle from D = 1/ ; 36 pc = 1/ , which gives = 0.028 ....
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CHAPTER 45 - 1 - CHAPTER 45 Astrophysics and Cosmology...

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