CHAPTER 45 - 1

CHAPTER 45 - 1 - CHAPTER 45 – Astrophysics and Cosmology...

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Unformatted text preview: CHAPTER 45 – Astrophysics and Cosmology Note: A factor that appears in the analysis of energies is e 2 /4p Å = (1.60 × 10 –19 C) 2 /4p(8.85 × 10 –12 C 2 /N ∙ m 2 ) = 2.30 × 10 –28 J ∙ m = 1.44 MeV ∙ fm. 1. Using the definition of the parsec, we find the equivalent distance in m: D = d / φ ; 1 pc = (1.50 × 10 11 m)/[(1.000 ″ )/(3600 ″ /°)(180°/p rad)] = 3.094 × 10 16 m. From the definition of the light-year, we have 1 pc = (3.094 × 10 16 m)/(3.00 × 10 8 m/s)(3.16 × 10 7 s/yr) = 3.26 ly. 2. We find the distance from D = 1/ φ = [1/(0.38 ″ )](3.26 ly/pc) = 8.6 ly . 3. We find the distance from D = 1/ φ = [1/(0.00019°)(3600 ″ /°)](3.26 ly/pc) = 4.8 ly . 4. ( a ) We find the parallax angle from D = 1/ φ ; 36 pc = 1/ φ , which gives φ = 0.028 ″ ....
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This note was uploaded on 09/13/2010 for the course PHYSICS 7 taught by Professor ? during the Spring '08 term at Berkeley.

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CHAPTER 45 - 1 - CHAPTER 45 – Astrophysics and Cosmology...

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