CHAPTER 45 - 6

# CHAPTER 45 - 6 - λ (2.7 K) = 2.90 × 10 –3 m ∙ K,...

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Unformatted text preview: λ (2.7 K) = 2.90 × 10 –3 m ∙ K, which gives λ = 1.1 × 10 –3 m = 1.1 mm . 32. We express the critical density in terms of the nucleon density from ρ c = M / V = nm n / V ; 10 –26 kg/m 3 = n (1.67 × 10 –27 kg)/ V , which gives n / V = 6 nucleons/m 3 . 33. If d ∝ 1/ T , when we form the ratio for two different times, we get d / d = T / T , where T = 2.7 K is the temperature today. ( a ) From Fig. 45–24 we estimate the temperature to be 3000 K, so we have d / d = T / T = (2.7 K)/(3000 K) ˜ 10 –3 . ( b ) From Fig. 45–24 we estimate the temperature to be 10 10 K, so we have d / d = T / T = (2.7 K)/(10 10 K) ˜ 10 –10 . ( c ) From Fig. 45–24 we estimate the temperature to be 10 13 K, so we have d / d = T / T = (2.7 K)/(10 13 K) ˜ 10 –13 ....
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## This note was uploaded on 09/13/2010 for the course PHYSICS 7 taught by Professor ? during the Spring '08 term at Berkeley.

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CHAPTER 45 - 6 - λ (2.7 K) = 2.90 × 10 –3 m ∙ K,...

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