CHAPTER 45 - 11 - p y / p = 2 GM / c 2 R . ( b ) When we...

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    p = – GMmR c d x x 2 + R 2 3/ 2 + = – GMmR c x R 2 x 2 + R 2 1/ 2 + = – 2 GMm cR = – 2 GMp c 2 R . = – ( GMm / cr 2 )( R / r ) d x   = – ( GMmR / c )[d x /( x 2  +  R 2 ) 3/2 ]. To find the total deflection we integrate over the path from  x  = – 8 to  x  = + 8: For the magnitude of the deflection angle we have ? θ  = – ?
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Unformatted text preview: p y / p = 2 GM / c 2 R . ( b ) When we use the data for the Sun, we get ? = [2(6.67 10 11 N m 2 /kg 2 )(2.0 10 30 kg)/(3.00 10 8 m/s) 2 (7.0 10 8 m)](180/p)(3600 /) = 0.87 ....
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