CHAPTER 43 - 6

# CHAPTER 43 - 6 - H 1 2 H 1 2 → H 1 3 H 1 1 H 1 2 H 1 2...

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Unformatted text preview: H 1 2 + H 1 2 → H 1 3 + H 1 1 H 1 2 + H 1 2 → He 2 3 + n H 1 2 + H 1 3 → He 2 4 + n 33. For the reaction , two atoms of 2 H, or 4 u, are used as fuel. The energy release is (4.03 MeV/reaction)/(4 u/reaction)(1.66 × 10 –27 kg/u) = 6.1 × 10 26 MeV/kg = 6.1 × 10 23 MeV/g . For the reaction , two atoms of 2 H, or 4 u, are used as fuel. The energy release is (3.27 MeV/reaction)/(4 u/reaction)(1.66 × 10 –27 kg/u) = 4.9 × 10 26 MeV/kg = 4.9 × 10 23 MeV/g . For the reaction , one atom of 2 H and one atom of 3 H, or 5 u, are used as fuel. The energy release is (17.59 MeV/reaction)/(5 u/reaction)(1.66 × 10 –27 kg/u) = 2.1 × 10 27 MeV/kg = 2.1 × 10 24 MeV/g . In the fission reaction, one atom of 235 U, or 235 u, is used as fuel. The energy release is (200 MeV/reaction)/(235 u/reaction)(1.66 × 10 –27 kg/u) = 5.1 kg/u) = 5....
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## This note was uploaded on 09/13/2010 for the course PHYSICS 7 taught by Professor ? during the Spring '08 term at Berkeley.

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CHAPTER 43 - 6 - H 1 2 H 1 2 → H 1 3 H 1 1 H 1 2 H 1 2...

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