CHAPTER 43 - 13 - C 6 12 + C 6 12 → Mg 12 24 K pr = K b +...

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Unformatted text preview: C 6 12 + C 6 12 → Mg 12 24 K pr = K b + Q . Because the kinetic energies « mc 2 , we can use a non relativistic treatment: K = mv 2 /2 = p 2 /2 m . The least kinetic energy is required when the product particles move together with the same speed. With the target at rest, for momentum conservation we have p b = p pr = m pr v , or K b = p b 2 /2 m b = ( m pr 2 /2 m b ) v 2 = ( m pr / m b ) K pr , or K pr = ( m b / m pr ) K b . When we use this in the kinetic energy equation, we get ( m b / m pr ) K b = K b + Q ; [( m b / m pr ) – 1] K b = Q , which gives K b = – Qm pr /( m pr – m b ). 69. ( a ) If we assume a thin target, we find the cross section for backward scattering from R / R = n σ x ; 1.6 × 10 –5 = (5.9 × 10 28 m –3 ) σ (4.0 × 10 –7 m), which gives σ = 6.8 × 10 –28 m 2 =...
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This note was uploaded on 09/13/2010 for the course PHYSICS 7 taught by Professor ? during the Spring '08 term at University of California, Berkeley.

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